fib=[] def fibo(a=-1,b=1,upto=4000000): if a+b>=upto: return else: a,b=b,a+b fib.append(b) fibo(a,b) fibo() even=[i for i in fib if not i%2] print sum(even)
Monday, February 23, 2009
Fibonacii series
I absolutely love this program I wrote to solve the Project Euler 2 nd problem
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